Question

intr un vas se gasesc 142g clor.Se ard in el 23 g de sodiu.a.)Ce cantitate de fier ar trebui arsa pentru a consuma clorul ramas? b)Ce cantitate de clorura de sodiu rezulta c)Cata clorura feric FeCl3 s a format?
#urgent!!!!!!!!!!Dau 20.de punctw

Answer 1

M,Na=23g/mol; M,Cl2= 71g/mol; M,NaCl= 58,5g/mol; M,FeCl3= 162,5g/mol

2mol......1mol.......2mol

2Na + Cl2----> 2NaCl

2x23g.....71g........2x58,5g

23g............x............y

x= 35,5g----> rest clor 35,5g

y= 58,5gNaCl

2mol...........3mol..........2mol

2Fe + 3Cl2---> 2FeCl3

2x56g 3x71g......2x162,5g

x...................35,5g...........y

x= 35,5x2x56/3x71=......................

y= 35,5x2x162,5/3x71=.......................calculeaza !!!!!

x=