Question

Întrebarea e în poză (ex. 4)​

Answer 1

Explicație pas cu pas:

5n+14/2n-7 €Z <=> 2n-7|5n+14

Avem:

2n-7|5n+14=> 2n-7|10n+28 (5n+14 /×2)

2n-7|2n-7=>2n-7|10n-35(2n-7 /×5)

Scadem si avem:

2n-7|10n+28-10n+35=> 2n-7|63 =>

2n-7€D63 in Z=>

2n-7€{-63,-21,-9,-7,-3,-1,1,3,7,9,21,63} =>

2n€{-54,-14,-2,0,4,6,8,10,14,16,28,70} =>

n€{-27,-7,-1,0,2,3,4,5,7,8,14,35}