Question

introdu intregii in urmatoarele fractii: a)2 4/5;b)3 1/9;c)6 3/4;d)7 2/3;e)5 1/4;f)15 1/7;g)1 8/15;h)2 9/25;i)4 2/15;j)1 1/2018

Answer 1

a) (2x5+4)/ 5=14/5
b) (3x9+1)/9=28/9
c) (6x4+3)/4=27/4
d) (7x3+2)/3=23/3
e) (5x4+1)/4=21/4
f)  (15x7+1)/7=106/7
g) (1x15+8)/15=23/15
h) (2x25+9)/25=59/25
i) (4x15+2)/15=62/15
j) (1x2018+1)/2018=2019/2018