Question

Introduceți factorii sub radical:

Answer 1

$b) - \frac{3}{4} \sqrt{3} = \sqrt{ {( - \frac{3}{4}) }^{2} \times 3 } = \sqrt{ \frac{9}{16} \times 3 } = \sqrt{ \frac{27}{16} }$

$- \frac{4}{9} \sqrt{5} = \sqrt{ {( - \frac{4}{9} )}^{2} \times 5} = \sqrt{ \frac{16}{81} \times 5} = \sqrt{ \frac{80}{81} }$

$- \frac{2}{3} \sqrt{7} = \sqrt{ {( - \frac{2}{3} )}^{2} \times 7} = \sqrt{ \frac{4}{9} \times 7} = \sqrt{ \frac{28}{9} }$

$- 5 \sqrt{7} = \sqrt{ {( - 5)}^{2} \times 7 } = \sqrt{25 \times 7} = \sqrt{175}$

$- 6 \sqrt{5} = \sqrt{ {( - 6)}^{2} \times 5} = \sqrt{36 \times 5} = \sqrt{180}$

$- 4 \sqrt{2} = \sqrt{ {( - 4)}^{2} \times 2 } = \sqrt{16 \times 2} = \sqrt{32}$

$7 \sqrt{10} = \sqrt{ {7}^{2} \times 10} = \sqrt{49 \times 10} = \sqrt{490}$

$c)5 \sqrt{14} = \sqrt{ {5}^{2} \times 14 } = \sqrt{25 \times 14} = \sqrt{350}$

$- 3 \sqrt{15} = \sqrt{ {( - 3)}^{2} \times 15 } = \sqrt{9 \times 15} = \sqrt{135}$

$- 8 \sqrt{6} = \sqrt{ {( - 8)}^{2} \times 6 } = \sqrt{64 \times 6} = \sqrt{384}$

$17 \sqrt{3} = \sqrt{ {17}^{2} \times 3} = \sqrt{289 \times 3} = \sqrt{867}$

$- 9 \sqrt{10} = \sqrt{ {( - 9)}^{2} \times 10} = \sqrt{81 \times 10} = \sqrt{810}$

$12 \sqrt{6} = \sqrt{ {12}^{2} \times 6 } = \sqrt{144 \times 6} = \sqrt{864}$

$- 6 \sqrt{7} = \sqrt{ {( - 6)}^{2} \times 7 } = \sqrt{36 \times 7} = \sqrt{252}$

$- 14 \sqrt{2} = \sqrt{ {( - 14)}^{2} \times 2 } = \sqrt{196 \times 2} = \sqrt{392}$

$d)12 \sqrt{7} = \sqrt{ {12}^{2} \times 7 } = \sqrt{144 \times 7} = \sqrt{1008}$

$13 \sqrt{5} = \sqrt{ {13}^{2} \times 5 } = \sqrt{169 \times 5} = \sqrt{845}$

$- 11 \sqrt{6} = \sqrt{ {( - 11) }^{2} \times 6} = \sqrt{121 \times 6} = \sqrt{726}$

$- \frac{8}{5} \sqrt{3} = \sqrt{ {( - \frac{8}{5} )}^{2} \times 3 } = \sqrt{ \frac{64}{25} \times 3 } = \sqrt{ \frac{192}{25} }$

$- \frac{5}{12} \sqrt{2} = \sqrt{ {( - \frac{5}{12} )}^{2} \times 2 } = \sqrt{ \frac{25}{144} \times 2} = \sqrt{ \frac{50}{144} } = \sqrt{ \frac{25}{72} }$

$18 \sqrt{3} = \sqrt{ {18}^{2} \times 3 } = \sqrt{324 \times 3} = \sqrt{972}$

$- 15 \sqrt{2} = \sqrt{ {( - 15)}^{2} \times 2} = \sqrt{225 \times 2} = \sqrt{450}$