Question

introduceti factorul sub radical
$2 \sqrt{3}$
$3 \sqrt{2}$
$6 \sqrt{5}$
$-5 \sqrt{6}$
$- 4 \sqrt{7}$
$7 \sqrt{3}$
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Answer 1

Explicație pas cu pas:

$2 \sqrt{3} = \sqrt{ {2}^{2} \times 3 } = \sqrt{12} \\ 3 \sqrt{2} = \sqrt{ {3}^{2} \times 2 } = \sqrt{18} \\ 6 \sqrt{5 } = \sqrt{ {6}^{2} \times 5} = \sqrt{36 \times 5} = \sqrt{180} \\ - 5 \sqrt{6} = \sqrt{ { - 5}^{2} \times 6} = \sqrt{25 \times 6} = \sqrt{150} \\ - 4 \sqrt{7 } = \sqrt{ { - 4}^{2} \times 7} = \sqrt{16 \times 7} = \sqrt{112}$