Question

Introduceti întregii in fractie 3 2/5 1 4/7 3 1/6 17 1/15 29 17/23 8 9/48

Answer 1

(3×5+2)/5=17/5=3,4
(1×7+4)/7=11/7
(3×6+1)/6=19/6
(17×15+1)/15=256/15
(29×23+17)/23=684/23
(8×48+9)48=393/48=131/16

Answer 2

3 intregi si 2/5 =  (3*5+2)/5 = 17/5
1 intreg  si 4/7 = (1*7+4)/7 = 11/7
3 intregi si 1/6 = (3*6+1)/6 = 19/6
17 intregi si 1/15 = (17*15+1)/15 = 256/15
29 intregi si 17/23 = (29*23+17)/23 = 684/23
8 intregi si 9/48 =(8*48+9)/48 = 393/48 

LA MULTI ANI,ROMANIA!!
1 DECEMBRIE 2017