Question

Introduceti intregii in fractiile:

a) 4$\frac{3}{29}$
b) 2$\frac{11}{43}$
c) 11$\frac{23}{57}$
d) 41$\frac{19}{701}$
e) 121$\frac{3}{119}$

Calculati:

a) $\frac{a}{19}+\frac{11a}{19}+\frac{7a}{19}$
b) $\frac{3a}{23}+\frac{17a}{23}+\frac{26a}{23}$
c) $\frac{11x}{49}+\frac{13x}{49}+\frac{25x}{49}$
d) $\frac{15b}{7}-\frac{3b}{7}-\frac{5b}{7}$
e) $\frac{21y}{11}-\frac{7y}{11}-\frac{3y}{11}$
f) $\frac{29c}{47}-\frac{21c}{47}-\frac{8c}{47}$

Answer 1

 [tex]1),Intregii\,se\,introduc\,in\,fractii\,astfel:\\ a)\;4\frac{3}{29}=\frac{29\cdot4+3}{29}= ...\\ b)\;2\frac{11}{43}=\frac{43\cdot2+11}{43}=...\\ c)\;11\frac{23}{57}= \frac{57\cdot11+23}{57}=...\\ d)\;41\frac{19}{701}=\frac{701\cdot41+19}{701}=...\\ e)\;121\frac{3}{119}=\frac{119\cdot121+3}{119}=...[/tex]
[tex]2).\\ a)\;...=19a / 19=a\;\\ b)\;...=46a / 23=2a\;\\ c)\;...=49x / 49=x\;\\ d)\;...=7b / 7 =b\;\\ e)\;...=11y / 11=y\;\\ f)\;...= 0\;[/tex]