Question

intru-n trunchi de puramida patrulatera regulata muchia laterala este de 1 dm si ariele bazelor de 18 cm 2 si 128 cm2 . afla inaltimea trunchiului de piramida

Answer 1

1.
apotema bazei mici=18:2=9
apotema bazei mari=24:2=12
12-9=3
h=√(6²-3²)=√(36-9)=√27=3√3
baza mare=24
baza mica=18
(24-18)/2=3
muchia=√(6²+3²)=√45=3√5
Abazei mici=18x18=324
Abazei mari=24x24=576
Pbazei mici=18x4=72
Pbazei mari=24x4=96
Alaterala=(72+96)x6/2=504
At=324+576+504=1404
V=h/3[Abazei mari+Abazei mici+√(Abazei marixAbazei mici)]=
 =3√3/3(324+576+√324x576)=3√3(324+576+432)=1332√3