Question

Intrun calorimetru se amestecă 1 kg apă la temperatura de 5 grade cu 5 kg apă la temperatura 90 grade c calcuati temperatura de echilibru

Answer 1

Se da:
m1=1kg
t1=5°C
m2=5kg
t2=90°C
c1=c2
t=?°C

Formule:
Q1=-Q2
c1*m1*Δt1=-c2*m2*Δt2
m1*(t-t1)=m2*(t2-t)
m1*t-m1*t1=m2*t2-m2*t
m1*t+m2*t=m2*t2+m1*t1
t*(m1+m2)=m2*t2+m1*t1
t=(m2*t2+m1*t1)/(m1+m2)

Calcule:
t=(1*5+5*90)/(1+5)=75,8(3)°C