Question

j) (256+3x+2x).12 = 4272;
k)[(x-28-2)-3+5].12 =1644;​

Answer 1

j) (256+3x+2x)•12=4272

(256+5x)•12=4272

3072+5x=4272

5x=4272-3072

5x=1200

x=1200:5

x=240

k) [(x-28-2)-3+5]•12=1644

[(x-26)-3+5]•12=1644

(x-26-3+15)•12=1644

(x-38)•12=1644

x-456=1644

x=1644+456

x=2100