Question

J)
$\frac{0.5 \div 1.25 + \frac{7}{5} \div 1 \frac{4}{7} - x }{(2.25 + \frac{1}{4}) \div 18 \frac{1}{3} } = 22 \frac{2}{3} = = > \\ \\ ................$

Answer 1

$\frac{ \frac{5}{10} : \frac{125}{100} + \frac{7}{5} : \frac{11}{7} - x}{( \frac{225}{100} + \: ^{25)} \frac{1}{4} ): \frac{55}{3} } = \frac{68}{3} = >$
$\frac{ \frac{5}{10} \cdot \frac{100}{125} + \frac{7}{5} \cdot \frac{7}{11} - x}{( \frac{225}{100} + \frac{25}{100} ): \frac{55}{3} } = \frac{68}{3} = >$
$\frac{ \frac{10}{25} + \frac{49}{55} - \: x }{ \frac{250}{100} \cdot \frac{3}{55} } = \frac{68}{3} = >$
$\frac{ \: ^{11)} \frac{2}{5} + \frac{49}{55} - \: ^{55)} x}{ \frac{3}{22} } = \frac{68}{3} = >$
$\frac{ \frac{22}{55} + \frac{49}{55} - \frac{55x}{55} }{ \frac{3}{22} } = \frac{68}{ 3} = >$
$\frac{ \frac{71}{55} - \frac{55x}{55} }{ \frac{3}{22} } = \frac{68}{3} = >$
$\frac{ \frac{71 - 55x}{55} }{ \frac{3}{22} } = \frac{68}{3} = >$
$\frac{71 - 55x}{55} : \frac{3}{22} = \frac{68}{3} = >$
$\frac{71 - 55x}{55} \cdot \frac{22}{3} = \frac{68}{3} = >$
$2( \frac{71 - 55x}{15} ) = \: ^{5)} \frac{68}{3} = >$
$\frac{142 - 110x}{15} = \frac{340}{15} = >$
$142 - 110x = 340 = >$
$- 110x = 340 - 142 = >$
$- 110x = 198 = >$
$x = \frac{198}{ - 110} ^{(2} = >$
$x = \frac{99}{ - 55} ^{(11} = >$
$x = - \frac{9}{5}$
$S= \{ - \frac{9}{5} \}$

Answer 2

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