Question

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Answer 1

Răspuns:

calculez mas C si masa H , stiind M,C=12g/mol,M,CO2=44g/mol

                                                       M,H= 1g/mol  M,h2o=18g/mol

44gCO2........12gC

6,6g..............m= 1,8gC

18gH2O..........2gH

3,6g.................m=0,4g

a)calculez compozitia procentuala:

2,2g compus.............1,8gC.................0,4gH

100G..........................x-81,8%C .......y= 18,2%H

deduc formula bruta

niuC= m/M= 81,8/12mol= 6,8molC

niuH= 18,2/1molH=18,2mol

IMPART prin cea mai mica valoare:   f.b.  CH2,68

DEDUC formula moleculara, stiind masa molara

44= n(12+2,68x1)------> n=3---------> f.m. C3H8   propan

b) CH3-CH2-CH3

c)C3H8+5O2---> 3CO2+4H2O

Explicație: