Question

Jumatatea sumei a 3 numere consecutive pare este 249. Afla numerele

Answer 1

$\frac{a + a + 2 + a + 4}{2} = 249$

$a + a + 2 + a + 4 = 2\times 249$

$3a + 6 = 498$

$3(a + 2) = 498 \: | \div 3$

$a + 2 = 166$

$a = 166 - 2$

$a = 164$

$a + 2 = 164 + 2 = 166$

$a + 4 = 164 + 4 = 168$