Question

K=1500N/m ,x=10cm(deformarea) En pot elastica =? Va rog sa ma ajutati!​

Answer 1

Răspuns:

delta l = 10cm = 0.01m

Epe = k × delta l² / 2

Epe = 1500N/m × 0.01m² / 2

(se simplifica 1500 cu 2 prin 2)

Epe = 750N/m × (1/100)²

Epe = 750N/m × 1/10000

(se simplifica 750 cu 10000 prin 250)

Epe = 3 × 1/40

Epe = 3/40 => 0.075 J

Sper ca te-am ajutat!