Question

KI+Cl2=2KCL+I2 aflati m(I) daca cantintatea (CL2) = 2mol
b)V (CL2)=56l
c)m(cl2)=355 g
va rog mult

Answer 1

M= 2x 127g/mol= 254g/mol I2
M= 2x 35,5g/mol= 71g/mol Cl2     si  Vm=22,4l/mol ptr.gaze
         1 mol              1mol
   2KI +Cl2 --> 2KCl+ I2
          2mol..............niu= 2 mol I2
b.        22,4l............22,4l
           56l...............V= 56l I2
C.       71g...........254g
           355g...........m--------------------------> calculeaza masa de iod !!!