Question

La 11 va rog frumos mulțumesc anticipat

Answer 1

a) D12 = {1 2 3 4 6 12}
2x+1=1
2x=0
x=0

2x+1=2
2x=1
x=0,5, nu e natural

2x+1=3
2x=2
x=1

2x+1=4
2x=3
x=3/2
x=1,5 nu e natural

2x+1=6
2x=5
x=5:2
x=2,5  nu e natural

2x+1=12
2x=11
x=5,5 nu e natural

Deci x ={0,1}

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b ) divizorii proprii a lui 6 sunt 2 si 3
x+1=2
x=1

x+1=3
x=2

Deci x={1,2}

Answer 2

[tex]11.a)D_1_2=1,2,3,4,6,12\\ =\ \textgreater \ 2x+1=1=\ \textgreater \ x=0\\ =\ \textgreater \ 2x+1=2=\ \textgreater \ x=0,5\\ =\ \textgreater \ 2x+1=3=\ \textgreater \ x=1\\ =\ \textgreater \ 2x+1=4=\ \textgreater \ x=1,5\\ =\ \textgreater \ 2x+1=6=\ \textgreater \ x=2,5\\ =\ \textgreater \ 2x+1=12=\ \textgreater \ x=5,5\\\\ cum~x~apartine~N=\ \textgreater \ x=0,1\\\\ x+1=3=\ \textgreater \ x=2(divizor~propriu~al~lui~6=3)\\ x=2 [/tex]