Question

La 3,4 va rog am nevoie urgent

Answer 1

3.

Q = 3.2 · 10⁻⁹ C

Stim ca q = 1.9 · 10⁻¹⁹ C

n = ?

Formula numarului de electroni transferati:

• n = Q/q

n = Q/q = (3.2 · 10⁻⁹)/(1.9 · 10⁻¹⁹) = 1.68 · 10⁻¹⁰ e⁻

Au fost transferati 1.68 · 10⁻¹⁰ electroni.

4.

q₁ = 8 μC = 8 · 10⁻⁶ C

q₂ = -2 μC = -2 · 10⁻⁶ C

d = 20 cm = 0.2 m

k = 9 · 10⁹ Nm²/C²

F = ?

Formula fortei de atractie:

• $F=k\frac{q_{1}q_{2}}{d^{2}}$

$F=k\frac{q_{1}q_{2}}{d^{2}}= 9*10^{9}\frac{8*10^{-6}*(-2)*10^{-6}}{0.2^{2}} =9*10^{9}\frac{(-16)*10^{-12}}{0.04} =\frac{(-144)*10^{-3}}{0.04} =\frac{-0.144}{0.04} = -3.6N$

Un alt exercitiu gasesti aici: https://brainly.ro/tema/8047145

#SPJ1