Question

La 3 acolo la final scrie 11/56! VA ROG AJUTAȚI-MĂ ​

Answer 1

1.

$\frac{12}{66}$

2.

$\frac{7}{23} + \frac{19}{46} - \frac{5}{23} - \frac{7}{46} = (aduci \: fractiile \: la \: acelasi \: numitor) \\ = \frac{14}{46} + \frac{19}{46} - \frac{10}{46} - \frac{7}{46} = \\ \frac{14 + 19 - 10 - 7}{46} = \\ \frac{16}{46} = \frac{8}{23}$

3. not. g-grau,p- porumb,f-floarea soarelui,l-legume

$g = \frac{11}{56} \\ p = \frac{13}{56} \\ f = \frac{1}{7}$

a.

$g + p = \frac{11}{56} + \frac{13}{56} = \frac{11 + 13}{56} = \frac{24}{56} = \frac{3}{7}$

b. legumele reprezinta restul suprafetei,deci vor fi diferenta dintre suprafata totala si suma celorlalte alimente

unde suprafata totala este 56/56

$l = \frac{56}{56} - (g + p + f) = \frac{56}{56} - ( \frac{11}{56} + \frac{13}{56} + \frac{1}{7} ) = \\ \frac{56}{56} - ( \frac{24}{56} + \frac{1}{7} ) = \frac{56}{56} - ( \frac{24}{56} + \frac{8}{56} ) = \frac{56}{56} - \frac{32}{56} = \frac{56 - 32}{56} = \frac{24}{56} = \frac{3}{7}$