Question

la 7 repede am nevoie ​

Answer 1

Răspuns:

Explicație:

  248g         xg      yg

   CuCO3=CuO +CO2

   124g       80g      44g

x=248. 80 : 124=160g CuO

y=248.44: 124=88gCO2

160g                      zg

  CuO + H2SO4= CuSO4 +H2O

80g                       160g

z=160.160:80=320g CuSO4

n=320g : 160g/moli=2moli CuSO4

88g                           w

 CO2 + Ca(OH)2 = CaCO3 + H2O

44g                            100g

w=88.100: 44=200g CaCO3

n= 200g : 100g/moli=2moli CaCO3

MCuCO3=64 + 12 +3.16=124----->124g/moli

MCuO=64 +16=80------>80g/moli

MC02 =12 +2.16=44----->44g/moli

MCuSO4=64 +32 +4.16=160----->160g/moli

MCaCO3=40+12+3.16=100------>100g/moli