Question

La exercitiul numarul 1
Va rog sa ma ajutati
Multumesc!

Answer 1

a)R=6

h=8

~ prin Teorema lui Pitagora aflam generatoarea

G=10

A bazei =ΠR la puterea a doua= 36Π

A laterala=ΠRG=60Π

A totala=Alaterala+Abazei=36Π+60Π=96Π

Volumul=Abazei ori inaltimea supra 3= 36Π*8/3=96Π

b) R=12

H=16

G=20

Ab=144Π

Al=240Π

At=144Π+240Π=384Π

V=768Π

c) H=12

G=13

R=5

Ab=25Π

Al=65Π

At=65Π+25Π=90Π

V=100Π

d) R=10

G=26

H=24

Ab=100Π

Al=260Π

At=360Π

V=800Π

e)G=15

R=12

H=9

Ab=225Π

Al=180Π

At=405Π

V=675Π

f)Ab=64Π=> R=8

V=128Π

H=6

G=10

Al=80Π

At=144Π