Question

la mate .Caiculeaza prin adunarea repetata de ierneni egali. Compara rezultatele .Ce ai observat? a)3×4 ;4×3; b)3×2; 2×3; c)3×5;5×3;d)3×7;7×3;e)3×9;9×3.​

Answer 1

Răspuns:

a)3+3+3+3=12

4+4+4=12

b)3+3=6

2+2+2=6

c)3+3+3+3+3=15

5+5+5=15

d)3+3+3+3+3+3+3=21

7+7+7=21

e)3+3+3+3+3+3+3+3+3=27

9+9+9=27

Eu observ ca in orice mod le-ai aduna, rezultatul rămâne același in toate cazurile

Answer 2

a)3×4,4×3

3×4=12

4×3=12

12=12

b) 3×2,2×3

3×2=6

2×3=6

6=6

c)3×5,5×3

3×5=15

5×3=15

15=15

d)3×7,7×3

3×7=21

7×3=21

21=21

e)3×9,9×3

3×9=27

9×3=27

27=27