Question

(la molecula gram): I. Cati moli sunt cuprinsi in a) 800g trioxid de sulf
b) 980g acid sulfuric
II. Cate molecule se gasesc in a) 10 moli apa
b)630g acid azotic
c) 17g amoniac

Answer 1

a) M SO3= A S +3×A O=32+3×16=32+48= 80 g /mol
1 mol SO3............. 80 g SO3
x moli SO3........... 800 g SO3
1/x=80/800=>x=10 moli SO3

b) M H2SO4= 2×A H + A S +4×A O =2×1+32+4×16= 2+32+64= 98 g/mol
1 mol H2SO4......... 98g H2SO4
x moli H2SO4........ 980 H2SO4
1/x=98/980=>x=10 moli H2SO4

1 mol H2O.=6_023×10²³ molecule
10 moli H20=n molecule
n=10×6,023×10²³ =6,023×10²⁴

M HNO3= A H +A N +3×A O =1+14+3×16= 1+14+48=63 g /mol
1 mol HNO3........ 63 g HNO3
x moli HNO3........ 630 g HNO3
1/x=63/630=>x=10 moli HNO3
1 mol HNO3 =6,023×10²³
10 moli =10× 6,023×10²³= 6,023×10²⁴


M NH3= A N +3×A H =14+3=17 g /mol
1 mol =6,023×10 ²³
17g = 6,023×10²³ molecule