Question

la o solutie de acid clorhidrik cu masa 40 g sa adaugt solutie AgNo3 Precipitatul format cintare 28,7 g Calculati partea de masa  HCl din solutia initiala 

Answer 1

HCl+AgNO3= AgCl(precipitat )+ HNO3
M( AgCl)) =143.5g/mol
Niu(AgCl)=m/M=28.7/143.5= 0.2 mol
Niu(AgCl)=Niu(HCl)=0.2mol
M(HCl) =36.5g/mol
m(HCl)=Niu*M=36.5*0.2= 7.3 g
ω=m(HCl)*100/m(sol HCl) =18.25 %