Question

La poza 2 este continuarea .. care nu s.a vazut ..

Answer 1

1)ipotenuza=4+4=8
cateta=√4x8=√32=4√2
Perimetrul=4√2 x2 +8=8√2+8 =8(√2+1)≈19,31 cm

2)AC=√(13²-12²)=√(169-144)=√25=5
AB²=BDx13
144=BDx13
BD=144/13
DC=13-144/13=(169-144)/13=25/13
AD=√(25/13x144/13)=5x12/13=60/13

3.sin 30 =1/2=3/AC 
AC=6
AC²=3xBC
36=3xBC
BC=36:3=12
AB=√9x12=√108=6√3

4.ipotenuza=√(6²+8²)=√(36+64)=√100=10

5. AB²=BDx26
100=BDx26
BD=100/26=50/13

AC²=DCx26
576=DC/26
DC=576/26=288/13