Question

la punctul c ,va rog !
legea compozitiei ​

Answer 1

x * (x+2) = 2(x+3)(x+2+3)-3

= (2x+6)(x+5)-3

= (2x²+10x+6x+30)-3

= 2x²+16x+27

Dar x * (x+2) = 3

=> 2x²+16x+27 = 3

2x²+16x+24 = 0

2(x²+8x+12) = 0

x²+8x+12 = 0

Δ = 64 - 48 = 16

x₁ = (-8+4)/2 = -4/2 = -2

x₂ = (-8-4)/2 = -12/2 = -6

Asadar x ∈ {-6, -2}