Question

La un aprozar se vinde toata cantitatea e caise la 4 cumparatotri .Primul cumpatra o doime si un kg. Al doilea cumpara o treime din rest si doua kg .Al treilea cumpara o patrime din rest si inca un kg iar al patrulea o doime din rest si un kg . Care a fost cantitatea initiala?

Answer 1

a=cantitatea caise
a/2+1 1 cumparator
a-a/2-1=a/2-1 rest
(a/2-1)× 1/3 +2 =a/6-1/3+2=a/6+5/3  al 2-lea cumparator
a/2-1-a/6-5/3 =2a/6-1-5/3=a/3-8/3 rest
(a/3-8/3) × 1/4 +1=a/12-2/3+1=a/12+1/3 al 3-lea cumparator
a/3-8/3-a/12-1/3=3a/12-8/3-1/3=a/4-3 rest
(a/4-3) × 1/2 +1 =a/8-3/2+1=a/8-1/2 al 4-lea cumparator
a/2+1+a/6+5/3+a/12+1/3+a/8-1/2=a
a/2+a/6+a/12+a/8+1+5/3+1/3-1/2=a
12a+4a+2a+3a+60=24a
3a=60
a=20 kg cantitate initiala
20/2+1=11 kg
20-11=9
9/3+2=5 kg
9-5=4
4/4+1=2 kg
4-2 =2
2:2+1=2 kg