Question

lg($x^{2}$-6x+5)-lg(3-x)=lg3

Answer 1

lg(x²-6x+5)/(3-x)=lg3
(x²-6x+5)/(3-x)=3
x²-6x+5-9-3x=0
x²-3x-4=0
x₁=4
x₂=-1

Answer 2

$x^{2} -6x+5=3*(3-x) \\ x^{2} -3x-4=0 \\ x_{1}=-1; x_{2}=4$
S={-1}