Question

lim 3x+2/4x+6, x->infinit

Answer 1

$\displaystyle \lim_{x \to \infty} \frac{3x+2}{4x+6} = \lim_{x \to \infty} \frac{x(3+ \frac{2}{x}) }{x(4+ \frac{6}{x} )} = \lim_{x \to \infty} \frac{3+ \frac{2}{x} }{4+ \frac{6}{x} } = \frac{3}{4}$