Question

Lim x tinde la 0 e^ax- e^bx supra mx urgent acum

Answer 1

l=lim f(x)=0/0  cand  x→0m Esti  in  conditiile  teoremei  lui  L Hospital
L=lim (e^ax-e^bx) `/(mx) `=(ae^ax-be^bx)/m=e^ax(a-b)/m=e^0(a-b)/m=(a-b)/m