Question

Limita când n tinde la plus infinit fin 2 la n plus 3 la n totul supra 4 la n plus 5 la n.
Multumesc anticipat!

Answer 1

$\displaystyle \limit\lim_{n\to \infty} \dfrac{2^n+3^n}{4^n+5^n}=\limit\lim_{n\to \infty}\dfrac{\left(\frac{2}{5}\right)^n+\left(\frac{3}{5}\right)^n}{\left(\frac{4}{5}\right)^n+1} =\dfrac{0+0}{0+1}=\boxed{0}$