Question

limita cand x tinde la 1 din 4x la a3a -6x la a2a +27 supra x-1

Answer 1

$\lim_{x \to 1} \frac{4x^3-6x^2+27}{x-1}= \frac{25}{0}$
E necesar de calculat limite laterale, Ls(1)=25/-0=-∞ iar Ld(1)=25/+0=+∞