Question

limite 167 ex e5 punctul a

Answer 1

Observam ca numitorul si numaratorul tind catre 0 asa ca vom aplica regula lui l'Hospital:
$\lim_{n \to \00} \frac{3^x-1}{6x} = \lim_{n \to \00} \frac{(3^x-1)'}{(6x)'} = \lim_{n \to \00} \frac{3^x ln 3}{6} = \frac{3^0 ln3}{6} = \frac{ln 3}{6}$