Question

(lnx - 1/x) totul derivat, iar x0 = 1

Answer 1

$\it \left(lnx-\dfrac{1}{x}\right)' =(lnx)'-\left(\dfrac{1}{x}\right)'= \dfrac{1}{x} -\left(\dfrac{-1}{x^2}\right)=\dfrac{1}{x} +\dfrac{1}{x^2}=\dfrac{x+1}{x^2}$