Question

log(4- x²)=log x+8 supra 3
    4           4

Answer 1

x∈(-2;2)
$4- x^{2} = \frac{x+8}{3} \\ 12-3 x^{2} =x+8 \\ 3 x^{2} +x-4=0$
Δ=49$x_{1}= \frac{-1-7}{6}=- \frac{8}{6}=- \frac{4}{3} \\ x_{2}= \frac{-1+7}{6}=1$