Question

log in baza 2 din 1\3+log in baza 4 din 9.

Answer 1

$\log_2\frac{1}{3}+\log_ 49=\log_23^{-1}+\log_{2^2}3^2=-\log_23+\frac{2}{2}\log_23=\\=-\log_23+\log_23=0$