Question

log4(4-x^2)=log4 x+8/3
urgennntttt , vă roooggg frumos​

Answer 1

4-x²>0 x∈(-2;2)

log in baza 4 din (4-x²)=log in baza 4 din ((x-8/3)

4-x²=(x+8)/3

12-3x²=x+8

3x²+x-4=0

x1,2=(-1+-√(1+48))/6=(-1+-7)/6

x1=-8/6=-4/3∈(-2;2)

x2=(-1+7)/6=6/6=1∈(-2;2)