Question

log7 (x+3)=log7 (2×-6)

Answer 1

$log_{7}(x + 3) = log_{7}(2x - 6)$

$x + 3 = 2x - 6$

$x - 2x = - 6 - 3$

$- x = - 9 \: | \times ( - 1)$

$x = 9$

Answer 2

[tex]\log _7\left(x+3\right)=\log _7\left(2x-6\right) \\ x+3=2x-6 \\ x+3-3=2x-6-3 \\ x=2x-9 \\ x-2x=2x-9-2x \\ -x=-9 \\ \frac{-x}{-1}=\frac{-9}{-1} \\ \\ x=9 \\ \\ [/tex]