Question

LOGARITMI:
  
1. log( rad 2) din2  + lg( rad de ordin 3 din 3) din3 =

2. log( 1 supra rad 5) din rad 125=
 
anexez doc
multumesc

8ea929cf762ab1a878164b1e2ad2fb86.docx

Answer 1

[tex]\displaystyle1)log_{\sqrt{2}}2+log_{ \sqrt[3]{3} }3=\\ = \frac{log_{2}2}{log_{2}2^{ \frac{1}{2} }} +\frac{log_{3}3}{log_{3}3^{ \frac{1}{3} }}=\\ = \frac{1}{ \frac{1}{2} } +\frac{1}{ \frac{1}{3} }=2+3=5\\ 2)log_{ \frac{1}{ \sqrt{5} } } \sqrt{125} = \frac{log_{5}5^{ \frac{3}{2} }}{log_{5}5^{- \frac{1}{2} }}=\\ = \frac{ \frac{3}{2} }{- \frac{1}{2} } =-3[/tex]Scrie răspunsul tău aici