Question

m=2011+2.(1+2+3+4+...2010)

Answer 1

   
[tex]\displaystyle M=2011+2(1+2+3+4+ \hdots +2010)= \\ \\ =2011+2 \times \frac{2010(2010+1)}{2} = \\ \\ = 2011 +2010 \times 2011 = \\ \\ = 2011(1+2010) = 2011 \times 2011 = \boxed{2011^2} = \boxed{4044121}[/tex]

Answer 2

m=2011+2*[2010*(2010+1)/2]
m=2011+2*2021055
m=4044121