Question

m(3-mx)+x+3-2(m+1)^2=0
determinati m pentru care x=-2​

Answer 1

m(3-mx)+x+3-2(m+1)²=0

x = -2 =>

m(3+2m)-2+3-2(m+1)² = 0

2m²+3m-2(m+1)²+1 = 0

2m²+3m-2(m²+2m+1)+1 = 0

2m²+3m-2m²-4m-2+1 = 0

-m-1 = 0

=> m = -1

Facem verificarea:

-(3+x)+x+3 = 0

-3-x+x+3 = 0

=> 0•x =0.

x = -2 => 0•(-2) = 0 (A)

=> m = -1