Question

(m+5)x^2-(m+7)x-m+3=0 x1+x2=x1x2

Answer 1

(m+5)x^2-(m+7)x-m+3=0
a=m+5
b=-m-7
c=-m+3
x₁+x₂=x₁x₂
x₁+x₂=-b/a =(m+7)/(m+5)
x₁x₂=c/a=(-m+3)/)m+5)
(m+7)/(m+5) =(-m+3)/)m+5)
m+7 =-m+3
2m=-4
m=-2
x₁+x₂=x₁x₂=5/3