Question

M.A a trei numere naturale consecutive este 186. determinati numerele

Answer 1

 [tex]m_a=\frac{a\;+\;a+1\;+\;a+2}{3}=186\\ \Downarrow\\ 3a+3=3\cdot186\\ 3a=555\\ a=185\;\\ \Rightarrow\;\;\;R:\;\;185\,;186\;;\,187[/tex]

Answer 2

186x2=372(suma)
a+a+1+a+2=372
ax3=372-3
ax3=369
a=369:3
a=123( primul numar)
123+1=124(al doilea numar)
123+2=125( al treilea numar)
proba:(123+124+125):2=372:2=186