Question

M.am chinuit 20 de minute la problema, dar degeaba, ma ajuta cineva? dau coroana
p.s EXERCITIUL NR 3

Answer 1

   
[tex]\displaystyle \\ \frac{12+3b}{18+2a} = 0,\!\!(6) \\ \\ \frac{12+3b}{18+2a} = \frac{6}{9} \\ \\ \frac{12+3b}{18+2a} = \frac{2}{3} \\ \\ 2(18+2a)=3(12+3b) \\ \\ \underline{36}+4a = \underline{36} + 9b \\ \\ 4a= 9b \\ \\ \frac{4a}{b} =9 \\ \\ \bold{\frac{a}{b} }= \boxed{\bold{\frac{9}{4} }}[/tex]