Question

m (CaO) = 11,2g
∨(CaO)-?
N)CaO)-?

Answer 1

$m_{CaO}=11.2g$

$M_{CaO}=40+16=56g/mol$

$n=\frac{m}{M}=\frac{11.2}{56}=0.2 moli$

$n=\frac{V}{22.4}$ ⇒ $V=n*22.4=0.2*22.4=4.48 L$
_______________________________________________________
m--->masa
M--->masa molara
n---->nr. de moli
V---->volum