Question

m=?
daca maximul functiei este egal cu 3
f(x)=mx^2+(2m-1)x+m+1​

Answer 1

f(x)=mx²+(2m-1)x+m+1

functia are maxim => m<0

Coordonatele varfului V(-b/2a; -Δ/4a); => -Δ/4m=3

Δ=(2m-1)²-4m(m+1)=4m²-4m+1-4m²-4m=1-8m

=>(8m-1)/4m=3

8m-1=12m;

-4m=1 => m= -1/4