Question

M1(x,x+1) si M2(1,0). Sa se determine x astfel incat M1M2=2√2

Dau raspuns cel mai bun. Va rog! Urgent!

Answer 1

M1M2=$\sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}}$= $\sqrt{(1-x)^{2}+[0-(x+1)^{2}] }$

=> M1M2= $\sqrt{(1-x)^{2}+[0-(x+1)^{2}] } =$ 2√2 

=> M1M2= $\sqrt{1+ x^{2} -2x- x^{2} -2x-1} =$ 2√2

=>M1M2=$\sqrt{-4x} =$ 2√2 $/^{2}$ => $8=-4x =\ \textgreater \ x=-2$