Question

m²+3m-4=0
m1 si m2=?

Answer 1

m² + 3m - 4 = 0
Δ = (-3)² - 4 * 1 * (-4) = 9 + 16 = 25. √25 = 5.
$m_{1}$ = $\frac{- 3 + 5}{2 * 1}$ = $\frac{2}{2}$ = 1.
$m_{2}$ = $\frac{-3 - 5}{2 * 1}$ = $\frac{-6}{2}$ = -3.
S = {-3, 1}