Question

Ma abonez la cine raspunde si dau coroana!
1) [(3^4-2^3*10): 6^0+5^12:25^6*5]*2^3

2) [(10^2-6^2):4^3+(7^2-3^2):10]:5

3) 4^25:(2*2)+(5^3+5^3*95):96-11^2​

Answer 1

Răspuns:

1)

$[(3^4-2^3\cdot10): 6^0+5^{12}:25^6\cdot5]\cdot2^3\\\\ \Big((81-8\cdot10): 1+5^{12}:(5^{2})^6\cdot5)\Big)\cdot8\\\\\Big((81-80): 1+5^{12}:5^{12}\cdot5)\Big)\cdot8\\\\\Big(1: 1+5^{12-12+1}\Big)\cdot8\\\\\Big(1+5^{1}\Big)\cdot8\\\\\Big(1+5\Big)\cdot8\\\\6\cdot8=\boxed{48}$

2)

$[(10^2-6^2):4^3+(7^2-3^2):10]:5\\\\\Big((100-36):4^3+(49-9):10\Big):5\\\\\Big(64:4^3+40:10\Big):5\\\\\Big(4^{3} :4^3+4\Big):5\\\\\Big(1+4\Big):5\\\\5:5=\boxed{1}$

3)

$4^{25}:(2\cdot2)+(5^3+5^3\cdot95):96-11^{2}}\\\\4^{25}:4+(5^3+95\cdot 5^{3}):96-11^{2}}\\\\\ 4^{25-1}+96\cdot 5^{3}:96-11^{2}}\\\\\ 4^{24}+1\cdot 5^{3}-121\\\\\ 4^{24}+5^{3}-121\\\\\ 4^{24}+125-121\\\\\ \boxed{4^{24}+4}$