Question

ma ajuta cineva cu aceasta tema?​

Answer 1

a=|2x+3|-4|2-(2x=5)|=-27

|2x+3|-4x|2-2x-5|=-27

|2x+3|-4x|-3-2x|=-27

|2x+3|-4x|-3-2x|=-27

|2x+3|-4x|-3-2x|=-27

|2x+3|-4x|-3-2x|=-27

|2x+3|-4x|-(2x+3)|=-27

|2x+3|=4x|2x+3|=-27

|2x+3|=9

2x+3=9

2x+3=-9

$x_{1}$=-6

$x_{2}$=3

b)$\frac{|x|-1}{4}-(\frac{|x|-2}{4}+\frac{7-2|x|}{5} \frac{|5x|-5}{10}-\frac{7}{4} =\frac{8x|x|-23}{20}$

$\frac{|x|-1}{4}-\frac{5(|x|-2)+4(7-2x|x|)}{20}$

$\frac{|x|-1}{4}-\frac{5x|x|-10+28-8x|x|}{20}$

$\frac{|x|-1}{4}-\frac{-3x|x|+18}{20}$

$\frac{5x|x|-5+3x|x|-18}{20}$

R=$\frac{-11x|x|-62+3x^{2} }{40}$

Restul sunt scrise in fișierul atașat