Question

Mă ajuta cineva repede am uitat cum se face:
(4+1 pe 16)
(4+1 pe 4)
(4+1 pe 8)

Answer 1

$a)4+ \frac{1}{16}(amplificam~pe~4~cu~16)= \frac{64}{16}+ \frac{1}{16}= \frac{65}{16}(nu~se~simplifica) \\ \\ b)4+ \frac{1}{4}(amplificam~pe~4~cu~4)= \frac{16}{4}+ \frac{1}{4}= \frac{17}{4}(nu~se~simplifica) \\ \\ c)4+ \frac{1}{8}(amplificam~pe~4~cu~8)= \frac{32}{8}+ \frac{1}{8}= \frac{33}{8}(nu~se~simplifica).$